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1.8 Β· Definition
What is a rational function? What are its zeros? When is it undefined?
p(x)/h(x) β zeros when p=0, undefined when h=0
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1.8 Β· Sign Chart Rule
When solving a rational inequality, what TWO types of values must appear on the sign chart?
Zeros AND undefined values
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1.8 Β· Endpoint Rule
For a rational inequality, when do you include vs exclude endpoints in the solution?
Think: zeros vs VAs, and < vs <=
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1.8 Β· Even Multiplicity
What happens to the sign at a zero or VA with EVEN multiplicity?
Same as polynomial multiplicity rule
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1.8 Β· Example 1
Solve (xβ2)/[(x+6)(xβ3)] >= 0. Answer in interval notation.
VAs: x=β6, x=3 Β· Zero: x=2
Sign: β, +, β, + at those four intervals
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1.8 Β· Example 3
Solve 2/(xβ3) > 0. Answer in interval notation.
Constant positive numerator β what matters?
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1.8 Β· Example 5
Solve (xβ1)(x+2)^2/(xβ2) >= 0. What is special about x=β2?
Even multiplicity zero β no sign change
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1.8 Β· Example 6
Solve 1/(xβ1)^2 <= 0. What is the answer?
Always positive expression β is there a solution?
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✓ Sign Chart Critical Values
BOTH zeros (num=0) AND undefined values (den=0)
Missing either type gives wrong signs on intervals. VAs are boundaries too β just never included in the solution.
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✓ Rational Function Definition
f(x) = p(x)/h(x) Β· Zeros: p(x)=0 Β· Undefined: h(x)=0
A ratio of two polynomials. Zeros make f(x)=0. Undefined values create vertical asymptotes or holes.
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✓ Even Multiplicity β No Sign Change
Sign stays SAME on both sides of the critical value
Even multiplicity (zero or VA) means the expression does NOT change sign at that point.
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✓ Endpoint Inclusion Rules
Zeros: include for <=/>= (closed) Β· VAs: NEVER include
Zeros (num=0): f=0 there, include for <= or >=. VAs (den=0): f undefined, always exclude with open bracket.
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✓ Example 3 β 2/(xβ3) > 0
Answer: (3, inf)
Numerator 2 is always positive. Sign follows denominator: negative for x<3, positive for x>3. VA at x=3 excluded.
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✓ Example 1 β Sign Chart Result
Answer: (β6, 2] U (3, inf)
VAs: x=β6, x=3 (open). Zero: x=2 (closed). Signs: β,+,β,+. Want >=0: (β6,2] and (3,inf).
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✓ Example 6 β 1/(xβ1)2 <= 0
Answer: No solution
1 > 0 always. (xβ1)^2 > 0 for all x not equal to 1. Expression is ALWAYS positive. Never <= 0.
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✓ Example 5 β (xβ1)(x+2)2/(xβ2) >= 0
Answer: (βinf, 1] U (2, inf)
x=β2 has even mult zero β no sign change. Signs: +,+,β,+. Want >=0: (βinf,1] and (2,inf). VA at x=2 excluded.