πŸ“Œ Part I β€” Solving Equations

We use log ↔ exponential conversion and log properties to solve. There are two main equation types:

Single log/exp
Isolate β†’ convert form β†’ solve
Multiple logs
Condense to one side β†’ Form 1 or Form 2
1
Isolate the log or exponential expression on one side
2
Convert to the alternate form (log ↔ exponential)
3
Solve for the variable
4
Simplify and leave in exact form (unless told to round)
a)
4Λ£ βˆ’ 2 = 7
4Λ£ = 9
x = logβ‚„ 9
b)
(2)x+3 + 5 = 26
(2)x+3 = 21
x = logβ‚‚ 21 βˆ’ 3
c)
βˆ’ex = 3 βˆ’ 4ex
3ex = 3 β†’ ex = 52
x = ln(52)
a)
2 log₃(x+3) + 4 = 10
log₃(x+3) = 3
x+3 = 27
x = 24
b)
2 + logβ‚…(2xβˆ’1) = 4
logβ‚…(2xβˆ’1) = 2
2xβˆ’1 = 25
x = 13
c)
ln(2βˆ’x)/5 = 1
ln(2βˆ’x) = 5
2βˆ’x = e⁡
x = 2 βˆ’ e⁡

Two End Forms

Form 1: logb(f) = c
β†’ Convert to exponential: f = bc
Form 2: logb(f) = logb(g)
β†’ Set equal: f = g
Always check for extraneous solutions! After solving, verify that all arguments of logarithms in the original equation are positive. Discard any solutions that make a log argument ≀ 0.
a)
log(3)+log(x+4)=log(5xβˆ’2)
log[3(x+4)] = log(5xβˆ’2)
3x+12 = 5xβˆ’2
x = 7 βœ“
b)
ln(x+1)βˆ’ln(3xβˆ’5)=ln7
ln[(x+1)/(3xβˆ’5)] = ln7
(x+1)/(3xβˆ’5) = 7
x = 9/5 βœ“
c)
log₃(x+2)+log₃(xβˆ’3)=log₃14
(x+2)(xβˆ’3)=14
xΒ²βˆ’xβˆ’20=0 β†’ x=5 or x=βˆ’4
x = 5 only (βˆ’4 fails domain)
d)
ln(x)βˆ’ln(3)=2
ln(x/3)=2
x/3 = eΒ²
x = 3eΒ²
a)
logβ‚„(x)βˆ’3logβ‚„2=logβ‚„(x+7)
logβ‚„(x/8)=logβ‚„(x+7)
x/8 = x+7 β†’ x = βˆ’8
No solution (x must be > 0)
b)
log(x)+3log(2)=log(2xβˆ’7)
log(8x)=log(2xβˆ’7)
8x = 2xβˆ’7 β†’ x = βˆ’76
No solution (x must be > 72)
Ex 5
ln(x+10)βˆ’ln(x)=ln(x+3)
ln[(x+10)/x]=ln(x+3)
x+10 = x(x+3) = xΒ²+3x
xΒ²+2xβˆ’10=0
x = (βˆ’2+√44)/2 β‰ˆ 2.317
(negative root rejected)
Ex 6
log₃(2xβˆ’3)+log₃(x+4)=log₃(8x+2)
(2xβˆ’3)(x+4)=8x+2
2xΒ²βˆ’3xβˆ’14=0
(2xβˆ’7)(x+2)=0
x = 72 only (βˆ’2 fails domain)
a)
25xβˆ’1 = 22x+7
5xβˆ’1 = 2x+7
x = 8/3
b)
83xβˆ’2 = 2x+5
(2Β³)3xβˆ’2 = 2x+5
9xβˆ’6 = x+5
x = 11/8
c)
92x = 27x+2
(3Β²)2x = (3Β³)x+2
4x = 3x+6
x = 6
d)
(1/2)5x+7 = 4x
2βˆ’5xβˆ’7 = 22x
βˆ’5xβˆ’7 = 2x
x = βˆ’1

Steps to Find f ⁻¹(x)

1
Switch x and y in the equation
2
Use inverse operations to solve for y (reverse order of operations)
3
Write the final answer as f ⁻¹(x) = ...
Ex 1: Find f ⁻¹
f(x) = 3(2)x+4 βˆ’ 15

y = 3(2)x+4 βˆ’ 15
β†’ switch x↔y:
x = 3(2)y+4 βˆ’ 15
(x+15)/3 = 2y+4
logβ‚‚((x+15)/3) = y+4
f⁻¹(x) = logβ‚‚((x+15)/3) βˆ’ 4
Ex 2: Find g ⁻¹
g(x) = βˆ’3logβ‚…(xβˆ’4) + 6

β†’ switch x↔y:
x = βˆ’3logβ‚…(yβˆ’4)+6
(6βˆ’x)/3 = logβ‚…(yβˆ’4)
5(6βˆ’x)/3 = yβˆ’4
g⁻¹(x) = 5(6βˆ’x)/3 + 4
Strategy: Isolate the expression, use log ↔ exp conversion, then apply a sign chart at critical x-values. Check domain restrictions first!

Example 4 β€” Log Inequality

f(x) = log((xΒ²βˆ’4x+7)/(x+3)) > 0    [Domain: x > βˆ’3]

log((xΒ²βˆ’4x+7)/(x+3)) > 0
β†’ argument must be > 1 (since log > 0 means argument > 10⁰ = 1)
xΒ²βˆ’4x+7 > x+3
xΒ²βˆ’5x+4 > 0
(xβˆ’1)(xβˆ’4) > 0
Solution: βˆ’3 < x < 1  or  x > 4

Example 5 β€” Compare Two Log Functions

g(x) = ln(xΒ²+xβˆ’5) < h(x) = ln(x+4)

ln((xΒ²+xβˆ’5)/(x+4)) < 0 β†’ argument < 1
xΒ²+xβˆ’5 < x+4 β†’ xΒ²βˆ’9 < 0 β†’ (x+3)(xβˆ’3) < 0
Solution: βˆ’3 < x < (βˆ’1+√21)/2  or  (βˆ’1+√21)/2 < x < 3  (with domain constraints)

Example 6 β€” Exponential Inequality

k(x) = 1 βˆ’ 4(2)xβˆ’3 ≀ βˆ’31
βˆ’4(2)xβˆ’3 ≀ βˆ’32
(2)xβˆ’3 β‰₯ 8 = 2Β³
xβˆ’3 β‰₯ 3
Solution: x β‰₯ 6
⚠️ AP Exam FRQ #4 β€” No Calculator Allowed

These problems require exact answers obtained through algebraic manipulation. Common approach: isolate, use log/exp properties, simplify carefully.

FRQ 1
f(x) = ex/4 / e3/5
Set f(x) = e7/4:
(x4) βˆ’ (35) = 74
x/4 = 74 + 35 = 43/20
x = 43/5
FRQ 2
g(x) = 8e3x βˆ’ ex
Set g(x) = 3ex:
8e3x = 4ex
e3x/ex = 1/2
e2x = 1/2
2x = ln(1/2) = βˆ’ln2
x = βˆ’ln2/2 = (1βˆ’ln2)/3
Careful: rewrite step-by-step
FRQ Tip: Leave answers in exact form (e.g., ln(52), not a decimal). Rewrite using properties before combining. Show all steps β€” partial credit is awarded for correct work even if the final answer has an error.
Strategy
What are the steps to solve an equation with a single log or exponential?
Tap to reveal ✨
Answer
Isolate β†’ Convert form (log↔exp) β†’ Solve β†’ Simplify
Step 1: get the log or exp alone. Step 2: rewrite in the other form. Step 3: solve for x. Step 4: leave exact form unless told to round.
Exponential & Log Equations
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Question 1 of 5
Solve for x (exact form): 4Λ£ βˆ’ 2 = 7
Isolate the exponential, then convert to log form
Question 2 of 5
Solve: 2 log₃(x + 3) + 4 = 10
Isolate the log, then convert to exponential form
Question 3 of 5
Solve: log₃(x+2) + log₃(xβˆ’3) = log₃14. Check for extraneous solutions.
Product Property, then set equal, then factor
Question 4 of 5
Solve: 92x = 27x+2 using common bases.
Rewrite 9 = 3Β² and 27 = 3Β³, then set exponents equal
Question 5 of 5
Find f ⁻¹(x) for f(x) = 3(2)x+4 βˆ’ 15.
Switch x and y, isolate the exponential, convert to log
0/5
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