When water fills at a constant rate, the height depends on the width of the vase at that level. Narrow section β height rises quickly. Wide section β height rises slowly.
Think of the graph as a roller coaster
Going up at that point β rate of change is positive.
Going down at that point β rate of change is negative.
At the very top of a peak or bottom of a valley β you are not moving up or down at that exact instant β rate of change is zero.
AP Precalculus vs. Calculus
In AP Precalculus, we cannot compute the exact rate of change at a single point β that requires calculus (it's called the derivative or instantaneous rate of change). We can only say whether it is positive, negative, or zero, and compare rates at two different points.
Key insight: "Least" means most negative
When comparing rates of change, least means the most negative value β the steepest downhill slope. A very steep downhill is a smaller (more negative) number than a gentle downhill.
How to tell if AROC is positive/negative/zero
AROC positive: output at the right endpoint is greater than at the left endpoint (overall going up on the interval).
AROC negative: output at the right endpoint is less (overall going down).
AROC zero: outputs at both endpoints are equal (same start and end, even if it wiggled in between).
The four questions to ask about each section
1. Is the function positive or negative? (above or below the x-axis)
2. Is the function increasing or decreasing? (going uphill or downhill)
3. Is the rate of change increasing or decreasing? (concave up βͺ or concave down β©)
4. Therefore: is the graph concave up or concave down?
| Section | Interval | p positive or negative? | p increasing or decreasing? | ROC increasing or decreasing? | Concave up or down? |
|---|---|---|---|---|---|
| A | 0 < x < 2 | Negative (x=0 to ~x=0.9) then Positive (~x=0.9 to x=2) |
Increasing β (outputs going up) |
Increasing (slope getting steeper) |
Concave Up βͺ |
| B | 2 < x < 4 | Positive (graph above x-axis) |
Decreasing β (outputs going down) |
Decreasing (slope getting less steep) |
Concave Down β© |
| C | 4 < x < 6 | Negative (graph below x-axis) |
Decreasing β (outputs going down) |
Increasing (slope becoming less negative) |
Concave Up βͺ |
| D | 6 < x < 8 | Negative (graph below x-axis) |
Increasing β (outputs going up) |
Increasing (slope getting steeper) |
Concave Up βͺ |
| E | 8 < x < 10 | Positive (graph above x-axis) |
Increasing β (outputs going up) |
Decreasing (slope getting less steep) |
Concave Down β© |
Key takeaway from section C
Section C is negative AND decreasing AND concave up. This is a common AP trap β the function is falling AND the rate of change is increasing at the same time. "Decreasing" refers to the outputs going down. "ROC increasing" means the slope is becoming less negative (e.g. going from β3 to β1). These are independent facts that can combine in any way.
(A) A to B (B) B to C (C) D to E (D) E to F
(A) Rate of change of k is negative on A to B (B) Rate of change of k is negative on B to C (C) Rate of change of k is positive on D to E (D) Rate of change of k is positive on E to F
(A) Rate of change is decreasing on A to B (B) Rate of change is increasing on B to C (C) Rate of change is increasing on D to E (D) Rate of change is decreasing on E to F
(A) A to B (B) B to C (C) C to D (D) D to E
(A) child age β height (B) points scored β time remaining (C) time β height of ball (D) radius β area
(A) k has a positive rate of change on [β10, 10] (B) k has a negative rate of change on [β10, 2.470] (C) k has a positive rate of change on [2.470, 10] (D) k has a negative rate of change on [2.470, 10]
(A) 1800β1850 (B) 1850β1900 (C) 1900β1950 (D) 1950β2000
| Option | Interval | Life Expectancy | AROC = Ξy / 50 |
|---|---|---|---|
| (A) | 1800 β 1850 | 41.24 β 46.10 | (46.10 β 41.24) / 50 = 0.097 |
| (B) | 1850 β 1900 | 46.10 β 53.63 | (53.63 β 46.10) / 50 = 0.151 |
| (C) β | 1900 β 1950 | 53.63 β 70.65 | (70.65 β 53.63) / 50 = 0.340 β Greatest |
| (D) | 1950 β 2000 | 70.65 β 81.83 | (81.83 β 70.65) / 50 = 0.224 |