📄 Page 1 — Questions FRONT · Sheet 1/2
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3.3 Β· P on Circle
A point P is at angle ΞΈ on a circle of radius r. What are the coordinates of P?
cos ΞΈ = x/r and sin ΞΈ = y/r
Multiply both sides by r
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3.3 Β· Axis Values
Give all 8 axis values: cos and sin for 0, Ο€/2, Ο€, and 3Ο€/2
The 4 axis points (1,0) (0,1) (βˆ’1,0) (0,βˆ’1)
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3.3 Β· Deriving Ο€/6
Derive cos(Ο€/6) and sin(Ο€/6) using an equilateral triangle.
y = 1/2, use xΒ² + yΒ² = 1
Q1 so x is positive
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3.3 Β· Deriving Ο€/4
Derive cos(Ο€/4) and sin(Ο€/4) using an isosceles right triangle.
x = y, use xΒ² + xΒ² = 1
Both values are equal
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3.3 Β· Ο€/3 Family
Give cos and sin for Ο€/3. Then state coordinates at 2Ο€/3, 4Ο€/3, and 5Ο€/3.
Q1 values then apply ASTC signs
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3.3 Β· Symmetry β€” ASTC
How do the signs of sin and cos change across the four quadrants?
All Students Take Calculus
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3.3 Β· Ex 7 β€” Q2 angle
Find sin(2Ο€/3) and cos(2Ο€/3).
2Ο€/3 is in Q2. Ref angle = Ο€/3.
Q2: sin positive, cos negative
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3.3 Β· Ex 7 β€” Q3 angle
Find cos(4Ο€/3) and sin(7Ο€/6).
Both in Q3. Ref angles: Ο€/3 and Ο€/6.
Q3: both negative
📄 Page 2 — Answers BACK · columns swapped
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✓ Axis Values (all 8)
cos0=1 sin0=0 Β· cos(Ο€/2)=0 sin(Ο€/2)=1 Β· cosΟ€=βˆ’1 sinΟ€=0 Β· cos(3Ο€/2)=0 sin(3Ο€/2)=βˆ’1
Points: (1,0) (0,1) (βˆ’1,0) (0,βˆ’1). cos=x-coord, sin=y-coord. (Example 3.)
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✓ P on Circle Formula
P = (r cosΞΈ, r sinΞΈ)
From cos=x/r and sin=y/r: multiply by r. Unit circle (r=1): P = (cosΞΈ, sinΞΈ).
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✓ Deriving Ο€/4
cos(Ο€/4) = √2/2 and sin(Ο€/4) = √2/2
Isosceles right: x=y. Then 2xΒ²=1 β†’ x=1/√2=√2/2. Both sin and cos equal √2/2.
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✓ Deriving Ο€/6
cos(Ο€/6) = √3/2 and sin(Ο€/6) = 1/2
Equilateral triangle: y=1/2. Then xΒ²+(1/2)Β²=1 β†’ x=√3/2 (positive in Q1).
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✓ Symmetry β€” ASTC Signs
Q1:(+,+) Q2:(βˆ’,+) Q3:(βˆ’,βˆ’) Q4:(+,βˆ’) [cos, sin]
All Students Take Calculus. All positive in Q1. Sin+ in Q2. Tan+ in Q3. Cos+ in Q4.
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✓ Ο€/3 Family
Ο€/3:(1/2,√3/2) 2Ο€/3:(βˆ’1/2,√3/2) 4Ο€/3:(βˆ’1/2,βˆ’βˆš3/2) 5Ο€/3:(1/2,βˆ’βˆš3/2)
Reference angle Ο€/3 in all four quadrants. Apply ASTC signs.
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✓ Ex 7 β€” Q3 Angles
cos(4Ο€/3) = βˆ’1/2 and sin(7Ο€/6) = βˆ’1/2
Q3: both negative. 4Ο€/3 ref Ο€/3: cos=βˆ’1/2. 7Ο€/6 ref Ο€/6: sin=βˆ’1/2. (Ex 7e,f.)
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✓ Ex 7 β€” Q2 Angle
sin(2Ο€/3) = √3/2 and cos(2Ο€/3) = βˆ’1/2
Q2: sin positive, cos negative. Ref angle Ο€/3 β†’ |sin|=√3/2, |cos|=1/2. (Ex 7a, 7i.)
📄 Page 3 — Questions FRONT · Sheet 2/2
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3.3 Β· Ex 7 β€” Q4 angle
Find cos(11Ο€/6) and sin(7Ο€/4).
11Ο€/6 in Q4 (ref Ο€/6). 7Ο€/4 in Q4 (ref Ο€/4).
Q4: cos positive, sin negative
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3.3 Β· Ex 7 β€” Special
Find cos(5Ο€/3) and sin(3Ο€/2).
5Ο€/3 is in Q4. 3Ο€/2 is on the βˆ’y axis.
📄 Page 4 — Answers BACK · columns swapped
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✓ Ex 7 β€” Special Values
cos(5Ο€/3) = 1/2 and sin(3Ο€/2) = βˆ’1
5Ο€/3: Q4, ref Ο€/3, cos=+1/2. 3Ο€/2: bottom of unit circle (0,βˆ’1), sin=βˆ’1. (Ex 7j, 7h.)
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✓ Ex 7 β€” Q4 Angles
cos(11Ο€/6) = √3/2 and sin(7Ο€/4) = βˆ’βˆš2/2
Q4: cos positive, sin negative. 11Ο€/6 ref Ο€/6: cos=√3/2. 7Ο€/4 ref Ο€/4: sin=βˆ’βˆš2/2. (Ex 7c, 7d.)